Question

In a reaction, $xA+yB\to zC$, if $-\frac{d\left[A\right]}{dt}=-\frac{d\left[B\right]}{dt}=1.5\frac{d\left[C\right]}{dt}$. Then $x,y$ and $z$ are:

• A. $1,1,1$
• B. $3,2,3$
• C. $3,3,2$
• D. $2,2,3$

Answer 1

The correct option is C $3,3,2$

For the reaction : $xA+yB\to zC$

$-\frac{1}{x}\frac{d\left[A\right]}{dt}=-\frac{1}{y}\frac{d\left[B\right]}{dt}=\frac{1}{z}\frac{d\left[C\right]}{dt}$.........(1)

Given that,

$-\frac{d\left[A\right]}{dt}=-\frac{d\left[B\right]}{dt}=1.5\frac{d\left[C\right]}{dt}$.........(2)

Multiplying equation 2 by $\frac{1}{3}$, we get

$-\frac{1}{3}\frac{d\left[A\right]}{dt}=-\frac{1}{3}\frac{d\left[B\right]}{dt}=\frac{1}{2}\frac{d\left[C\right]}{dt}$.........(3)

On comparing equation 1 and 3, we get value of

$x=3,$ $y=3,$ $z=2$

Hence, option C is correct.