Question

In a rectangle $ABCD,BC=2AB$. The moment of inertia is minimum along axis through.

• A. $BC$
• B. $CD$
• C. $HF$
• D. $EG$

Answer 1

The correct option is C $HF$

Since along edges moment of inertia is greater than middle axis by $4m{r}^2$ comparing axis $EG$ and $HF$,

Moment of inertia $=\frac{M{\left(AE\right)}^2}{12}$ and $\frac{{M\left(\frac{AB}{2}\right)}^2}{2}$

respectively $=\frac{M{\left(AB\right)}^2}{12}$ and $\frac{1}{4}\frac{1}{4}$

So about $HF$ moment of inertia is very low.