You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Area of Rectangle

In a rectangl...

Question

In a rectangle ABCD, M and N are the midpoints of the sides BC and CD respectively. If $ˆ A N M = 90^{0}$ then AB:BC is

2:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2} : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{3} : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\sqrt{2} : 1$
In $Δ M C N, t a n θ = \frac{y}{x}$ and In $Δ A D N, t a n (90 - 0) = \frac{2 y}{x}$
$c o t θ = \frac{2 y}{x}$
$t a n θ = \frac{x}{2 y}$
$2 y^{2} = x^{2}$
$\frac{x}{y} = \frac{\sqrt{2}}{1}$

Suggest Corrections

Similar questions

A B C D

is a parallelogram and

A_{1}

and

B_{1}

are the midpoints of sides

B C

and

C D

, respectively. If

- - \to A A_{1} + - - \to A B_{1} = λ - - \to A C

, then

λ

is equal to

Q. If E, F, G and H are respectively the midpoints of the sides AB, BC, CD and AD of a parallelogram ABCD, show that

a r (E F G H) = \frac{1}{2} a r (A B C D)

ABCD is a rectangle formed by the points A(-1, -1), B(-1, 4), C(5, 4) and D(5, -1). If P,Q,R and S be the midpoints of AB, BC, CD and DA respectively, show that PQRS is a rhombus.

P, Q, R, S

are respectively the midpoints of the sides

A B, B C, C D

and

D A

1 g m

A B C D .

Show that

P Q R S

is a parallelogram and also show that
at

(1 g m

P Q R S) = \frac{1}{2} \times a r (1 g m

A B C D) .

Q. In a rectangle

A B C D

P

Q

R

and

S

are the midpoints of the sides

A B

B C

C D

and

D A

respectively. Find the area of

P Q R S

in terms of area of

A B C D

Join BYJU'S Learning Program

In a rectangle ABCD, M and N are the midpoints of the sides BC and CD respectively. If ˆANM=900 then AB:BC is

The correct option is C √2:1In ΔMCN,tanθ=yx and In ΔADN,tan(90−0)=2yxcotθ=2yxtanθ=x2y2y2=x2xy=√21

In a rectangle ABCD, M and N are the midpoints of the sides BC and CD respectively. If $ˆ A N M = 90^{0}$ then AB:BC is

The correct option is C $\sqrt{2} : 1$
In $Δ M C N, t a n θ = \frac{y}{x}$ and In $Δ A D N, t a n (90 - 0) = \frac{2 y}{x}$
$c o t θ = \frac{2 y}{x}$
$t a n θ = \frac{x}{2 y}$
$2 y^{2} = x^{2}$
$\frac{x}{y} = \frac{\sqrt{2}}{1}$