In a rectangle, if the length is increased by 3 metres and breadth is decreased by 4 metres, the area of the rectangle is reduced by 67 square metres. If length is reduced by 1 metre and breadth is increased by 4 metres, the area is increased by 89 sq. metres. Find the dimensions of the rectangle.
Let the length= l and breadth= b
According to the question-
Area of rectangle -
(l+3)(b−4)=lb−67 [∵ Area of rectangle =l×b]
⇒lb−4l+3b−12=lb−67
⇒−4l+3b=−55
it can also be written as
⇒4l−3b=55 ---(1)
Again according to the question-
Area of rectangle
(l−1)(b+4)=lb+89
⇒lb+4l−b−4=lb+89
⇒4l−b=93−−−(2)
subtracting (2 )from (1)-
4l−4l−3b+b=55−93
⇒−2b=−38
⇒b=19
putting this value in equation (1), we get
4l−3(19)=55
⇒4l−57=55
⇒4l=112
⇒l=28
Hence, length =28 m breadth =19 m