In a rectangle $R E N T$ , the diagonals meet at $O$ . If $O R = 2 x + 4$ and $O T = 3 x + 1$ , find $x$

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Solution

Observe that $O R = O T$ (diagonal bisect each other and they are equal in a rectangle). Hence
$2 x + 4 = 3 x + 1$ .
This implies that $4 - 1 = 3 x - 2 x = 3 = x$ .
Hence $x = 3$ .

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