In a rectangle the breadth is one unit less than the length and the area is $12$ sq.units. Find the length of the rectangle.

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Solution

The correct option is A $4$
Let the length be $x$ , then the breadth will be $(x - 1)$
Are is given by $x \times (x - 1) = 12$
$\Rightarrow x^{2} - x - 12 = 0 \Rightarrow (x - 4) (x + 3) = 0$
$\Rightarrow x = 4$ and $x = - 3$
Since the length cannot be negative, the length of the rectangle is $4$ .

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In a rectangle the breadth is one unit less than the length and the area is 12 sq.units. Find the length of the rectangle.

The correct option is A 4Let the length be x, then the breadth will be (x−1)Are is given by x×(x−1)=12⇒x2−x−12=0⇒(x−4)(x+3)=0⇒x=4 and x=−3Since the length cannot be negative, the length of the rectangle is 4.

In a rectangle the breadth is one unit less than the length and the area is $12$ sq.units. Find the length of the rectangle.

The correct option is A $4$
Let the length be $x$ , then the breadth will be $(x - 1)$
Are is given by $x \times (x - 1) = 12$
$\Rightarrow x^{2} - x - 12 = 0 \Rightarrow (x - 4) (x + 3) = 0$
$\Rightarrow x = 4$ and $x = - 3$
Since the length cannot be negative, the length of the rectangle is $4$ .