Question

Question 82

In a rectangular plot, 5 square flower beds of side (x+2) metres each have been laid (see the figure). Find the total cost of fencing the flower beds at the cost of Rs. 50 per 100 meters.

Answer 1

Given, side of one square flower bed = (x + 2) m
$\therefore$ Perimeter of one square flower bed = 4 (Side) = 4(x + 2) m
Now, total perimeter of 5 such square flower beds = $5\times$ Perimeter of one square
$=5\times 4(x+2)$
= 20(x + 2) m
$\because$ Cost of fencing of 100 m = Rs. 50
$\therefore$ Cost of fencing of 1 m = Rs. $\frac{50}{100}$
$\therefore$ Cost for $20(x+2)m=\frac{50}{100}\times 20(x+2)=10(x+2)$
= Rs. (10x + 20)