In a redox reaction, how many moles of electrons are accepted by 1 mole of $M n O_{4}$ in acidic medium?

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\frac{5}{2}

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Solution

The correct option is B 5
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$

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