In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to other. A charged particle is released from rest in this region. The path of the particle will be a:
A
circle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
helix
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
straight line
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
ellipse
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C straight line Given :In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to other. A charged particle is released from rest in this region.
Solution :
Particle will experience electric force FE=qE in the direction of electric field.
Formula for magnetic field FB=q(→V×→B)
And velocity vector and magnetic field are parellal as electric field and magnetic field are parellal. So particle will experience magnetic force FB=0.Since cross product of parellal vectors is 0.