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Question

In a region, the potential is represented by V(x,y,z)=2xy4yyz+3zx, where V is in Volts and x, y and z are in meters. The electric force experienced by a charge of 5 coulomb at the point (1, 2, 1) is 5n. Find n

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Solution

Given:
V(x,y,z)=2xy4yyz+3zx
q=5 C
Point =(1, 2, 1)
As we know that,

Ex(1, 2, 1)= Vx

Ex(1, 2, 1)=x(2xy4yyz+3zx)

Ex(1, 2, 1)=(2y+3z)=(2×2+3×1)

Ex(1, 2, 1)=7 N/C

Ey(1, 2, 1)= Vy

Ey(1, 2, 1)=y(2xy4yyz+3zx)

Ey(1, 2, 1)=(2x4z)=(2×141)

Ex(1, 2, 1)=3 N/C

Ez(1, 2, 1)= Vz

Ez(1, 2, 1)=z(2xy4yyz+3zx)

Ez(1, 2, 1)=(y+3x)=(2+3×1)

Ex(1, 2, 1)=1 N/C

E=(E2x+E2y+E2z)=(72+32+(1)2)

E=59 N/C

Now F=qE=5×59=559 N

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