In a regular hexagon ABCDEF- AB -a- BC -b- and CD -c- Then- AE -

The correct option is C b⃗+c⃗ According to the question........... [ In regular #160; hexagon: its side line is,; ...

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Area Based Approach

In a regular ...

Question

In a regular hexagon $A B C D E F$ , $¯ ¯¯¯¯¯¯ ¯ A B = a, ¯ ¯¯¯¯¯¯ ¯ B C = \to b$ and $¯ ¯¯¯¯¯¯¯ ¯ C D = \to c$ . $T h e n, ¯ ¯¯¯¯¯¯ ¯ A E =$

\to a + \to b + \to c

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2 \to a + \to b + \to c

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\to b + \to c

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\to a + 2 \to b + 2 \to c

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Solution

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[\to a + 2 \to b - \to c, \to a - \to b, \to a - \to b - \to c] =

\to a

\to b

\to c

\frac{[\begin{matrix} \to a + 2 \to b & \to b + 2 \to c & \to c + 2 \to a \end{matrix}]}{[\begin{matrix} \to a & \to b & \to c \end{matrix}]}

\to a, \to b, \to c

[\to a \to b \to c] = \frac{4}{7}

[2 \to a - \to b, 2 \to b - \to c, 2 \to c - \to a]

\to a, \to b

\to c

\to b + \to c, \to c + \to a

\to a + \to b

| \to a + \to b | = 6, | \to b + \to c | = 8

| \to c + \to a | = 10

| \to a + \to b + \to c |

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

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