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Question

In a regular hexagon ABCDEF, ¯¯¯¯¯¯¯¯AB=a,¯¯¯¯¯¯¯¯BC=b and ¯¯¯¯¯¯¯¯¯CD=c. Then,¯¯¯¯¯¯¯¯AE=

A
a+b+c
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B
2a+b+c
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C
b+c
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D
a+2b+2c
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Solution

The correct option is C b+c
According to the question...........
Inregularhexagon:itssidelineis,AB=BC=DE=EF=AF¯¯¯¯¯¯¯¯AE=¯¯¯¯¯¯¯¯¯BD¯¯¯a=¯¯b=¯¯c=lIntriangleABCD[Usetrianglelawodedition,¯¯¯¯¯¯¯¯BC+¯¯¯¯¯¯¯¯¯CD=¯¯¯¯¯¯¯¯¯BD¯¯b+¯¯c=¯¯¯¯¯¯¯¯¯BD=¯¯¯¯¯¯¯¯AEThen,¯¯¯¯¯¯¯¯AE=¯¯b+¯¯cSo,thatthecorrectoptionisC.
1188211_1085748_ans_d02ba2d659854d898c8ba9937967c7ce.png

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