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B
−−→AC+−−→AF−−−→AB
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C
−−→AC+−−→AB−−−→AF
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D
−−→AC+−−→AB−−−→AD
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Solution
The correct option is B−−→AC+−−→AF−−−→AB −−→AE=−−→AB+−−→BC+−−→CD+−−→DE =−−→AC+−−→AF+−−→DE (−−→AF is parallel and equal to −−→CD) =−−→AC+−−→AF+−−→BA(−−→BA=−−→DE,−−→BA∥−−→DE) −−→AE=−−→AC+−−→AF−−−→AB