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Covalent Bond

In a regular ...

Question

In a regular octahedral molecule, $M X_{6}$ the number of X-M-X bonds at an angle of $180^{\circ}$ is

Three

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Two

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Six

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Four

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Solution

The correct option is B Three
b' $M X_{6}$
$3 180^{c i r c}$ angles
$X_{1} - M - X_{4}$
$X_{2} - M - X_{5}$
$X_{3} - M - X_{6}$ '

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