In a regular polygon of n sides, each corner is at a distance r from the centre. Identical charges are placed at (n-1) corners. At the centre, the magnitude of intensity is E and the potential is V.The ratio V/E is

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r(n-1)

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(n-1)/r

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r(n-1)/n

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Solution

The correct option is B r(n-1)
At the centre, the intensity is effectively due to one charge and the potential is due to $(n - 1)$ charges
$∴ E = \frac{k Q}{r^{2}}; V = \frac{k (n - 1) Q}{r}$
Hence, $\frac{V}{E} = \frac{k (n - 1) Q}{r} \times \frac{r^{2}}{k Q} = (n - 1) r$

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In a regular polygon of n sides, each corner is at a distance r from the centre. Identical charges are placed at (n-1) corners. At the centre, the magnitude of intensity is E and the potential is V.The ratio V/E is

The correct option is B r(n-1)At the centre, the intensity is effectively due to one charge and the potential is due to (n−1) charges∴E=kQr2;V=k(n−1)QrHence, VE=k(n−1)Qr×r2kQ=(n−1)r

The correct option is B r(n-1)
At the centre, the intensity is effectively due to one charge and the potential is due to $(n - 1)$ charges
$∴ E = \frac{k Q}{r^{2}}; V = \frac{k (n - 1) Q}{r}$
Hence, $\frac{V}{E} = \frac{k (n - 1) Q}{r} \times \frac{r^{2}}{k Q} = (n - 1) r$