Question

In a reversible reaction, if concentration of reactants are doubled, the equilibrium constant K will:

• A. change to $1/4$ K
• B. change to $1/2$ K
• C. change to $2$ K
• D. remains the same

Answer 1

The correct option is D remains the same

(D) remains the same

because the equilibrium constant have a constant fixed value and remains the same.

Hence, option $D$ is correct.