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Question

In a reversible reaction, the study of its mechanism says that both the forward and reverse reaction follows first order kinetics. If the half-life of forward reaction (t1/2)f is 400s and that of reverse reaction (t1/2) b is 250s, the equilibrium constant of the reaction is:

A
1.3
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B
0.433
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C
0.625
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D
1.109
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Solution

The correct option is D 0.625
K=KfKb
Equilibrium Constant=0.693t1/2(f)0.693t1/2(b)

Equilibrium Constant=250400

Equilibrium Constant=0.625

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