Question

In a rhombus $ABCD,\angle CBA={40}^{\circ }$.
Find the other angles.

Answer 1

$\angle B={40}^o$

Rhombus is also a parallelogram. Hence the opposite angle are equal.

$\therefore \angle D=\angle B={40}^o$

Further is a parallelogram,

ad jaunt angles add upto ${180}^o$

$\Rightarrow \angle A +\angle B =180^o\Rightarrow \angle A+40^o=180^o\Rightarrow\angle A =180^o-40^o=140^O$

opposite angles are equal , hence $\angle A=\angle C={140}^o$

Thus all angles are as shown below:

$\angle A={140}^o,\angle B={40}^o,\angle C={140}^o,\angle D={40}^o$