Question

In a rhombus $ABCD$, its diagonals intersect at ${}^{\prime }{O}^{\prime }$. Then $\angle AOB=$ ___________ .

Answer 1

$ABCD$ is a rhombus.

$AC$ and $BD$ are diagonals of rhombus.

We know that, diagonals of a rhombus bisect each other perpendicularly .

$\therefore$ $AC\perp BD$

$i.e.AO\perp BO$

$\therefore$ $\angle AOB={90}^o$