Question

In a right angle triangle ABC, $\angle A$ is right angle DE is parallel to the hypotenuse BC and the length of DE is 65% the length of BC, what is the area of $\Delta ADE,$ if the area of $\Delta ABC$ is $68c{m}^2$ ?

• A. $27.83c{m}^2$
• B. $41.6c{m}^2$
• C. $28.73c{m}^2$
• D. None of the above

Answer 1

The correct option is C

$28.73c{m}^2$

$\frac{Areaof\Delta ABC}{Areaof\Delta AED}=(\frac{BC}{0.65BC}{)}^2=\frac{1}{0.4225}\therefore Areaof\Delta AED=0.4225\times 68=28.73c{m}^2$