In a right angle triangle ABC (right angled at B), find the value of tanA×tanC.
We know tanA=Opposite sideAdjacent side ∴tanA=BCAB
and tanC=ABBC
So, tanA×tanC=(BCAB)×(ABBC)=1
In a right angled triangle ABC (right angled at B),
the value of tan A ✕ tan C = _______.