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Question

In a right angle ABD, in which B=60o and A=30o.

Then, tan60o is equal to

453628_67dd6b65c9e5484fae4d0f46c6a0c442.PNG

A
2
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B
12
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C
3
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D
13
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Solution

The correct option is B 3
Consider an equilateral ABC with each side =2a.
So each angle is 60.
From A, draw AD to BC,
so BD=DC=a and ADB=90o,BAD=30o.
So, for ADB, we have AD=AB2BD2
=(2a)2a2=4a2a2=3a2=3a.
tan60o=ADBD=3aa=3



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