In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 $m^{2}$ .Find the base and height of the triangle. [3 MARKS]

Open in App

Solution

Concept : 1 Mark
Application : 1 Mark
Calculation : 1 Mark

Let one side be x and the other side will be (x- 2)

Then, Area of a triangle = $(\frac{1}{2}) \times b a s e \times h e i g h t$
i.e., 60 $m^{2} = [(\frac{1}{2}) \times (x - 2) \times x]$
$\Rightarrow$ Therefore by solving this eqn $\Rightarrow$ x = 10 and -12

Now by neglecting x = -12 and taking x = 10

Base and height = 10 cm and 8 cm

Suggest Corrections

Similar questions

Q. The lengths of the two sides of a right triangle containing the right angle differ by 2 cm. If the area of the triangle is 24 cm², find the perimeter of the triangle.

Q. Find the height of a right angled triangle if it's area is

22

m^{2}

and its base is

2 m

Q. The difference between the sides at right angle in a right-angled triangle is 7 cm. The area of the triangle is 60 cm². Find its perimeter.

Q. The sides (in cm) of a right angle triangle containing right angle are

5 x

and

(3 x - 1)

. If the area of the triangle is

60 c m^{2}

. Find its perimeter.

The difference between two adjoining sides containing right angle of a right angled triangle is 14cm . The area of a tristria is 120cm . Verify the area using herons formula.

Join BYJU'S Learning Program

In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 m2.Find the base and height of the triangle. [3 MARKS]

In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 $m^{2}$ .Find the base and height of the triangle. [3 MARKS]