In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 $m^{2}$ .Find the base and height of the triangle. [3 MARKS]

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Solution

Concept : 1 Mark
Application : 1 Mark
Calculation : 1 Mark

Let one side be x and the other side will be (x- 2)

Then, Area of a triangle = $(\frac{1}{2}) \times b a s e \times h e i g h t$
i.e., 60 $m^{2} = [(\frac{1}{2}) \times (x - 2) \times x]$
$\Rightarrow$ Therefore by solving this eqn $\Rightarrow$ x = 10 and -12

Now by neglecting x = -12 and taking x = 10

Base and height = 10 cm and 8 cm

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In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 m2.Find the base and height of the triangle. [3 MARKS]

In a right angle triangle board the difference between the two sides containing right angle is 2m and the area of the triangle is 60 $m^{2}$ .Find the base and height of the triangle. [3 MARKS]