Question

In a right angled triangle $ABC,\angle B={90}^{\circ }$ such that $AB=6cm,BC=8cm$. Then find $AC$.

• A. $13cm$
• B. $14cm$
• C. $10cm$
• D. $12cm$

Answer 1

The correct option is C $10cm$

By using Pythagoras theorem in $△ABC,$

$A{C}^2=A{B}^2+B{C}^2$

$\Rightarrow A{C}^2=6^2+8^2$

$\Rightarrow A{C}^2=36+64$

$\Rightarrow A{C}^2=100$

$\Rightarrow AC=10cm$