Question

In a right angled $△ABC$, right-angled at B, $\angle A+\angle C$ =

• A. 90${}^{\circ }$
• B. 120${}^{\circ }$
• C. 180${}^{\circ }$

Answer 1

The correct option is A 90${}^{\circ }$

Consider the right angled $△ABC$, right-angled at B.
The angle sum property of a triangle states that the sum of the interior angles of any triangle is 180${}^{\circ }$.
So, $\angle A+\angle B+\angle C={180}^{\circ }$
$⟹\angle A+\angle C={180}^{\circ }-{90}^{\circ }={90}^{\circ }$, since $\angle B={90}^{\circ }$