In a right angled triangle ABC (right angled at B),

the value of tan A ✕ tan C = _______.

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Solution

The correct option is A 1

From the above figure,
$t a n A = \frac{B C}{A B}$

$t a n C = \frac{A B}{B C}$

So,
$t a n A \times t a n C = (\frac{B C}{A B}) ✕ (\frac{A B}{B C}) = 1$

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Similar questions

In a right angle triangle ABC (right angled at B), find the value of $tan A \times tan C$ .

5 \times s i n A = 3

c o s C + t a n A + c o s e c C .

tan A = cot B

5 \times s i n A = 3

5 \times s i n A = 3

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