In a right angled △ABC, right angled at B, which of the following is true?
AC2 = AB2 + BC2
In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, In the right angled △ABC, right angled at B, AC is the hypotenuse and AB and BC are the other two sides.
Hence, AC2=AB2+BC2