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Question

In a right angled triangle ABC right angled at C, tanB=3 then sinA+sinB is equal to

A
3+12
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B
3
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C
{12}
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D
1
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Solution

The correct option is A 3+12
In the triangle ABC,
tan B=3
sinA=12
sinB=32

Since,
=sinA+ sinB
=12+32
=3+12

Hence, this is the answer.

1175122_374795_ans_8d639341300d41e3ade79c0af635273a.jpg

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