In a right angled triangle if the base is 3 cm and perpendicular is 4 cm. What is the area of that triangle?

$8 c m^{2}$

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$6 c m^{2}$

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$7 c m^{2}$

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$9 c m^{2}$

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Solution

The correct option is B
$6 c m^{2}$

Area of a triangle $= (\frac{1}{2}) \times base \times height = \frac{1}{2} \times 4 \times 3$

$= 6 c m^{2}$

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In a right angled triangle if the base is 3 cm and perpendicular is 4 cm. What is the area of that triangle?

The correct option is B 6 cm2 Area of a triangle =(12)×base×height=12×4×3 =6 cm2

The correct option is B
$6 c m^{2}$

Area of a triangle $= (\frac{1}{2}) \times base \times height = \frac{1}{2} \times 4 \times 3$

$= 6 c m^{2}$