Question

In a right angled triangle, one of the acute angles exceeds the other by ${20}^0.$, Find the measure of the both the acute angles in the right angled triangle.

Answer 1

Given in a right angle triangle one angle exceeds other by ${20}^o$.

$\angle B=\angle C+20$

$\angle A+\angle B+\angle C={180}^o$

$\angle B+\angle C=180-90={90}^o$

$2\angle C=90-20=70$

$[\angle C={35}^o]$

& $[\angle B={55}^o]$.