Question

In a right angled triangle, the length of perpendicular and base are $8cm$ and $15cm$ respectively, then find its hypotenuse.

Answer 1

In a right triangle, by Pythagoras theorem:
$(Hypotenuse{)}^2=(Perpendicular{)}^2+(Base{)}^2$
$A{C}^2=A{B}^2+B{C}^2$
$=8^2+{15}^2$
$=64+225=289$

Taking square roots on both sides, we get
$\therefore HypotenuseAC=\sqrt{289}=17cm$.