In a right-angled triangle, the length of the largest side is 10 cm and of another side is 8 cm. What will be the length of the remaining side?

5 cm

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6 cm

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7 cm

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8 cm

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Solution

The correct option is B 6 cm
Given, the triangle is right-angled.
Hence, we can apply Pythagoras theorem.

Let the remaining side be $x$ cm.
$H y p o t e n u s e^{2} = B a s e^{2} + A l t i t u d e^{2}$
$10^{2} = 8^{2} + x^{2}$
$x^{2} = 10^{2} - 8^{2} = 100 - 64$
$x^{2} = 36$
$x = 6 c m$

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In a right-angled triangle, the length of the largest side is 10 cm and of another side is 8 cm. What will be the length of the remaining side?

The correct option is B 6 cmGiven, the triangle is right-angled. Hence, we can apply Pythagoras theorem. Let the remaining side be x cm. Hypotenuse2=Base2+Altitude2 102=82+x2 x2=102−82=100−64 x2=36 x=6 cm

The correct option is B 6 cm
Given, the triangle is right-angled.
Hence, we can apply Pythagoras theorem.

Let the remaining side be $x$ cm.
$H y p o t e n u s e^{2} = B a s e^{2} + A l t i t u d e^{2}$
$10^{2} = 8^{2} + x^{2}$
$x^{2} = 10^{2} - 8^{2} = 100 - 64$
$x^{2} = 36$
$x = 6 c m$