In a right-angled triangle, the length of the largest side is 10cm and that of another side is 8cm. Then the length of the third side is equal to

4cm

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6cm

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7cm

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12cm

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Solution

The correct option is B 6cm
We know that if the given triangle is right-angled, then the sides follow Pythagoras theorem.

Let the length of the third side be x cm.

$\to 10^{2} = 8^{2} + x^{2}$
$\to 100 - 64 = x^{2}$

$⟹$ $x = 6 c m$

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Question 35

If the length of two sides of a triangle are 6 cm and 10 cm, then the length of the third side can be

a) 3 cm
b) 4 cm
c) 2 cm
d) 6 cm

The corresponding sides of 2 similar triangles $△ A B C$ and $△ P Q R$ are in the ratio 5:2. Given that AB=3 cm and AC=10 cm,the length of side PR (in cm) is___________.

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In a right-angled triangle, the length of the largest side is 10cm and that of another side is 8cm. Then the length of the third side is equal to

The correct option is B 6cmWe know that if the given triangle is right-angled, then the sides follow Pythagoras theorem. Let the length of the third side be x cm. → 102=82+x2 → 100−64=x2 ⟹ x=6cm

The correct option is B 6cm
We know that if the given triangle is right-angled, then the sides follow Pythagoras theorem.

Let the length of the third side be x cm.

$\to 10^{2} = 8^{2} + x^{2}$
$\to 100 - 64 = x^{2}$

$⟹$ $x = 6 c m$