Question

In a right angled triangle, with respect to an acute angle $\theta$, the opposite side is twice the adjacent side. Find the value of cosec$\theta$.

• A. √5/2
• B. √3/2
• C. √2/3
• D. 5/2

Answer 1

The correct option is A

√5/2

Let the length of adjacent side be x

According to question, opposite side = 2x

Using Pythagoras theorem,

$A{C}^2=A{B}^2+B{C}^2$

$A{C}^2=(x{)}^2+(2x{)}^2$

AC = $\sqrt{5}$ x

cosec$\theta$ = $\frac{hypotenuse}{oppositeside}$ =$\frac{\sqrt{5}}{2}$