Question

In a right triangle ABC, $\angle B={90}^{\circ }$ . If $AB=6$ cm, $BC=8$ cm, find $AC$.

Answer 1

Given, $\angle B={90}^o,AB=6$ cm, $BC=8$ cm

Therefore,

$A{C}^2=A{B}^2+B{C}^2$ ....... pythagoras theorem
$=6^2+8^2$

$=36+64=100$

Thus, $AC=$ $\sqrt{100}=10$