In a right triangle ABC, right angled at B. AB = 5 cm, BC = 12 cm, find AC.

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Solution

In a right triangle ABC,
AB = 5 cm, BC = 12 cm

Using Pythagoras Theorem,
That is,
$A C^{2}$ = $A B^{2}$ + $B C^{2}$
=> $A C^{2}$ = $5^{2}$ + $12^{2}$
=> $A C^{2}$ = 25 + 144
=> $A C^{2}$ = 169
=> AC =  $\sqrt{169}$
=> AC = 13
Thus, the length of side AC = 13cm.

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In a right triangle ABC, right angled at B. AB = 5 cm, BC = 12 cm, find AC.

In a right triangle ABC, AB = 5 cm, BC = 12 cm Using Pythagoras Theorem, That is, AC2 = AB2 + BC2 => AC2 = 52 + 122 => AC2 = 25 + 144 => AC2 = 169 => AC =  √169 => AC = 13 Thus, the length of side AC = 13cm.