Question

In a right triangle PQR and DEF, if $hypotenusePQ=hypotenuseEF$ and side $PR=DE$ then $△PQR\cong$ $△.....$

• A. $EFD$
• B. $EDF$
• C. $DEF$
• D. $FED$

Answer 1

The correct option is A $EFD$

In $△PQR$ and $△DEF$,
$PQ=EF$ (Given)
$\angle R=\angle D$ (Each ${90}^{\circ }$)
$PR=DE$ (Given)
Thus, $△PQR=△EFD$ (RHS rule)