In a right triangle, sum of the squares of two sides is equal to the square of the hypotenuse.

By following these steps of construction,

(i) Draw a line segment PQ = 11 cm

(ii) At P construct an angle of 60o and at Q, an angle of 45^o.

(iii) Bisect these angles. Let the

bisectors of these angles intersect at a point A.

(iv)Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

(v). Join AB and AC. Triangle ABC has been obtained. In this ABC,

AB + BC + CA > 11cm

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AB + BC = 11cm

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AB + BC + CA = 11cm

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BC + CA = 11cm

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Solution

The correct option is C
AB + BC + CA = 11cm

AB + BC + CA = 11cm

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Similar questions

By following these steps of construction,

(i) Draw a line segment PQ = 11 cm

(ii) At P construct an angle of 60^o and at Q, an angle of 45^o.

(iii) Bisect these angles. Let the bisectors of these angles intersect at a point A.

(iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

(v). Join AB and AC. Triangle ABC has been obtained. In this ∆ABC,

Q. By following these steps of construction,

(i) Draw a line segment PQ = 11 cm

(ii) At P construct an angle of 60^o and at Q, an angle of 45^o.

(iii) Bisect these angles. Let the bisectors of these angles intersect at a point A.

(iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

(v). Join AB and AC. Triangle ABC has been obtained. In this ∆ABC,

The steps to construct a triangle with given base angles $∠$ B and $∠$ C and BC + CA + AB, are:.
A. Draw a line segment, say XY equal to BC + CA + AB.
B. Make $∠$ LXY equal to $∠$ B and MYX equal to $∠$ C.
C. Bisect $∠$ LXY and $∠$ MYX. Let these bisectors intersect at a point A.
D. Draw perpendicular bisectors PQ of AX and RS of AY.
E. Let PQ intersect XY at B and RS intersect XY at C. Join AB and AC.

Q. To construct a triangle ABC in which

∠ B = 60^{\circ}, ∠ C = 45^{\circ}

and AB + BC + AC = 12 cm

The steps of construction are:
Step 1: Draw a line segment XY=12 cm
Step 2: At X, construct an angle of $60^{\circ}$ and at y construct an angle of $45^{\circ}$
Step 3: Bisect these angles. Let bisector of these angles intersect at point A
Step 4 will be

Pallav got following question in his exam:

Given the base angles, say $∠$ B and $∠$ C and BC + CA + AB, construct triangle ABC.

He followed the following steps for the construction.

1. Draw a line segment, say XY equal to BC + CA + AB.

2. Make $∠$ LXY equal to $∠$ B and $∠$ MYX equal to $∠$ C.

3. Bisect $∠$ LXY and $∠$ MYX. Let these bisectors intersect at a point A

4. Draw perpendicular bisectors PQ of AX and RS of AY.

5. Let PQ intersect XY at B and RS intersect XY at C. Join AB and AC

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The correct option is C AB + BC + CA = 11cmAB + BC + CA = 11cm

The correct option is C
AB + BC + CA = 11cm

AB + BC + CA = 11cm