In a right triangle the square of the hypotenuse is equal to twice the product of the legs. One of the acute angles of the triangle is:

15^{o}

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30^{o}

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45^{o}

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60^{o}

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75^{o}

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Solution

The correct option is C $45^{o}$
$c^{2} = 2 a b; ∴ a^{2} + b^{2} = 2 a b; ∴ {(a - b)}^{2} = 0$ and
$a = b$ since the right triangle is isosceles, one of the acute angles is $45^{o}$

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In a right triangle the square of the hypotenuse is equal to twice the product of the legs. One of the acute angles of the triangle is:

The correct option is C 45oc2=2ab;∴a2+b2=2ab;∴(a−b)2=0 anda=b since the right triangle is isosceles, one of the acute angles is 45o

The correct option is C $45^{o}$
$c^{2} = 2 a b; ∴ a^{2} + b^{2} = 2 a b; ∴ {(a - b)}^{2} = 0$ and
$a = b$ since the right triangle is isosceles, one of the acute angles is $45^{o}$