In a right triangle with sides a and b and hypotenuse c,the altitude drawn on the hypotenuse is x. Then:
A
a.b= x2
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B
1a+1b=1x
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C
a2+b2=2x2
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D
1x2=1a2+1b2
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E
1x=ba
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Solution
The correct option is E1x2=1a2+1b2 The segments of the hypotenuse are a2c and
b2c.Using similar triangles,xa=b2cb,xb=a2ca. ∴x2=a2cb2c=a2.b2a2+b2; and ∴1x2=1a2+1b2.