wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a rigid body in plane motion, the point R is accelerating with respect to point P at 10180o m/s2. If the instantaneous acceleration of point Q is zero acceleration (in m\s2) of point R is


A
8233o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10225o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10217o
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8217o
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8217o

As acceleration of point Q is zero, therefore we can assume this rigid body PQR is hinged at Q at this instant.

aRP=aRaP

It is given as 10 m/s2 at an angle of 180o, that means only radial acceleration is there at that instant and reference is PR.

aRP=(RP)ω2=10

20ω2=10

ω=12

Since point R has only radial acceleration, so total acceleration is only radial. therefore tangential acceleration is zero.

αbody=0

aR=QR(ω2)=16×12=8 m/s2

and will be in the horizontal backward direction,by our reference is along PR, so the angle of it from reference is (180+θ) from ΔPQR

tanθ=1216

θ=36.8698o

So,180+36.8698=216.8698270o
So the answer is 8217o

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon