CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Staggered Conformation

In a sample o...

Question

In a sample of calcium phosphate ,Ca_3(PO_{4)}, 0.432 moles of phosphorous is present, what is amount of calcium phosphate is present in the sample if sample is 100% pure

Open in App

Solution

Ca3(PO4)2 contains 0.432 moles of phosphorous.
moles of Ca3(PO4)2=20.432=0.216mole
Molar mass of Ca3(PO4)2=3×40+2(31+64)
=310g
Moles of it = 310×0.216=66.96g
≈67g

Suggest Corrections

thumbs-up

38

Similar questions

Q. The ratio of phosphorous atoms present in calcium phosphide and magnesium phosphate is:

Q. Matrix composed of calcium and phosphate is present in __________.

Q. An ore contains calcium hydroxide

C a (O H)_{2}

in association with calcium phosphate

C a_{3} (P O_{4})_{2}

. The analysis shows that calcium and phosphorous are present is a mole ratio of 5:3, which of the following best represent the composition of the ore?

Q. Number of moles of calcium ions and phosphate ions present in half mole of calcium phosphate are respectively.

State True or False.

Decomposition of calcium phosphate present in bone ash with concentrated sulphuric acid produces phosphoric acid.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Conformational Isomerism

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Staggered Conformation

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon