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Staggered Conformation

In a sample o...

Question

In a sample of calcium phosphate ,Ca_3(PO_{4)}, 0.432 moles of phosphorous is present, what is amount of calcium phosphate is present in the sample if sample is 100% pure

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Solution

Ca3(PO4)2 contains 0.432 moles of phosphorous.
moles of Ca3(PO4)2=20.432=0.216mole
Molar mass of Ca3(PO4)2=3×40+2(31+64)
=310g
Moles of it = 310×0.216=66.96g
≈67g

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