The correct option is C 6
All the possible transitions emit radiation either in the ultraviolet, visible or infrared band.
So, the number of lines in the infrared region = total emitted lines −(Number of lines in the visible region + Number of lines in the ultraviolet region)
We know that, n=6 for the 5th excited state.
Total emitted lines for transition, n1=6→n2=1=(n1−n2)(n1−n2+1)2=15
Since all the lines falling onto n=2 are in the visible band, the number of lines in the visible region = 4(transitions from 6→2, 5→2, 4→2, 3→2)
Since all the lines falling onto n=1 are in the ultraviolet band, the number of lines in the ultraviolet region =5(transitions from 6→1, 5→1, 4→1, 3→1,2→1)
Now, No. of lines in Infrared region = 15−4−5=6