Question

In a sand casting process, a sprue of 10 mm base diameter and 250 mm height leads to a runner which fills a cubical mould cavity of 100 mm size.

$\text{The volume flow rate (in}m{m}^3/s\text{) is}$

• A. $2.3\times {10}^5$
• B. $1.1\times {10}^5$
• C. $1.7\times {10}^5$
• D. $0.8\times {10}^5$

Answer 1

The correct option is C $1.7\times {10}^5$

$\text{Given data:}$

$\text{D = 10 mm,}{h}_s\text{= 250 mm}$

$\text{Velocity of metal at sprue end,}$

$V_s=\sqrt{2g{h}_s}=\sqrt{2\times 9.81\times 250\times {10}^3}mm/s$

$A_c=\frac{\pi }{4}\times {10}^2=78.53m{m}^2$

$\text{Flow rate =}{V}_s{A}_c=173942.13m{m}^3/s$