Question

In a school, $38\%$ of the students are girls. If the number of boys is $1023.$ Find the total strength of the school.

Answer 1

Let the total number of students in the school be $x$.
Total number of boys $=1023$
Percentage of number of girls $=38\%$
Percentage of number of boys $=(100-38)\%=62\%$

Percentage of boys $=\frac{\text{Number of boys}}{\text{Total strength}}\times 100\%$

$62\%=\frac{1023}{x}\times 100\%$

$\Rightarrow x=\frac{1023}{62}\times 100$

$\Rightarrow x=16.5\times 100$

$\Rightarrow x=1650$

Hence, the total strength of the school is $1650.$