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Question

In a school all the students have to learn drawing or painting. If 36% of the students learn drawing and painting and 40% of those who learn drawing do not learn painting, then what % of the students learn painting?



Your Answer
A

40%

Your Answer
B

60%

Correct Answer
C

76%

Your Answer
D

80%


Solution

The correct option is C

76%


If we assume the total number of students = 100

As the students need to learn draing or painting, n(D U P) = 100.

n(DP) = 36.

Let n(D) = x

Then the number of students who do not paint represents the set of students who only draw,i.e. D - P

n(D - P) = 0.4x.

Thus,0.4x+36=xx=60

n(DP)=n(D)+n(P)n(DP)

100 = 60 + n(P) - 36

n(P) = 100 - 24

n(P) = 76%

Alternate: n(P)=n(DP)+n(PD)

                   n(P) = 36 + (100 - 60)

                           = 36 + 40

                           = 76%

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