Question

In a school, the strength is 8th, 9th and 10th standards are respectively 48, 42 and 60. Find the least number of books required to be distributed equally among the classes of 8th, 9th and 10th standard.

Answer 1

It is given that in a school, the strength is 8th, 9th and 10th standards are respectively $48$, $42$ and $60$. Therefore,

$48$, $42$ and $60$ can be factorised as follows:

$48=2\times 2\times 2\times 2\times 342=2\times 3\times 760=2\times 2\times 3\times 5$

The least number of books can be obtained by finding the $LCM$ of $48$, $42$ and $60$.

We know that $LCM$ is the least common multiple, therefore, the $LCM$ of $48$, $42$ and $60$ is:

$LCM=2\times 2\times 2\times 2\times 3\times 7\times 5=1680$

Hence, $1680$ books are required to be distributed equally among the classes of 8th, 9th and 10th standard.