In a school there are 10 periods per day of 40 minutes each. Students want to reduce the number of periods but the principal doesn't want to reduce the number of working hours. How can the principal to reduce the number of periods to 8 without changing the total working hours?

30 minutes

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55 minutes

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50 minutes

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45 minutes

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Solution

The correct option is C
50 minutes

$\begin{matrix} N u m b e r o f p e r i o d s & 10 & 8 T i m e f o r e a c h p e r i o d (I n m i n u t e s) & 40 & y \end{matrix}$
$10 \times 40 = 8 \times y \leftrightarrow y = \frac{10 \times 40}{8} = 50 m i n u t e s$ .

Make periods each of 50 minutes.

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In a school there are 10 periods per day of 40 minutes each. Students want to reduce the number of periods but the principal doesn't want to reduce the number of working hours. How can the principal to reduce the number of periods to 8 without changing the total working hours?

The correct option is C 50 minutes Number of periods108Time for each period(In minutes)40y 10×40=8×y↔y=10×408=50 minutes. Make periods each of 50 minutes.

The correct option is C
50 minutes

$\begin{matrix} N u m b e r o f p e r i o d s & 10 & 8 T i m e f o r e a c h p e r i o d (I n m i n u t e s) & 40 & y \end{matrix}$
$10 \times 40 = 8 \times y \leftrightarrow y = \frac{10 \times 40}{8} = 50 m i n u t e s$ .

Make periods each of 50 minutes.