In a school there are 120 students, who participated in Cricket and Football. 50 of them played both games. The sum of number of students who played exactly one game and number of students who played none of the game is ___.

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Solution

Sum of number of students who played exactly one game and number of students who played none of the games $= (C \cap F)^{c}$
$= C^{c} \cup F^{c}$
= 120 - 50 = 70

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In a school there are 120 students, who participated in Cricket and Football. 50 of them played both games. The sum of number of students who played exactly one game and number of students who played none of the game is ___.

Sum of number of students who played exactly one game and number of students who played none of the games =(C∩F)c =Cc∪Fc = 120 - 50 = 70

Sum of number of students who played exactly one game and number of students who played none of the games $= (C \cap F)^{c}$
$= C^{c} \cup F^{c}$
= 120 - 50 = 70