Question

In a scientific book that describes a temperature scale called $Z$, boiling and freezing point of water are referred as ${65}^{o}Z$ and $-{15}^{o}Z$ respectively. (a) To what temperature on Fahrenheit scale would a temperature $-{95}^{o}Z$ compound? (b) What temperature change on the $Z$ scale that would correspond to a change of ${40}^o$ on Celsius scale?

Answer 1

Freezing Point $=-15°z$

Boiling Point $=65°z$

$\left(a\right)\left[T°F\right]=\left[T°Re\right]\times \frac{9}{4}+32$

$\left[T°F\right]=[-95°z]\times \frac{9}{4}+32$

$\left[T°F\right]=-181.75°F$

$\therefore -95°z=-181.75°F$

$\left(b\right)\left[T°Z\right]=\left[T°C\right]\times \frac{4}{5}$

$T°Z=40°C\times \frac{4}{5}$

$T°Z=32°Z$

$\therefore 40°C=32°Z$